(X+y)^2+3X+y=4026

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Solution for (X+y)^2+3X+y=4026 equation: 



(X+X)^2+3X+X=4026

We move all terms to the left:

(X+X)^2+3X+X-(4026)=0

We add all the numbers together, and all the variables

(+2X)^2+3X+X-4026=0

We add all the numbers together, and all the variables

4X+(+2X)^2-4026=0

We move all terms containing X to the left, all other terms to the right

4X+(+2X)^2=4026

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